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How to calculate the weight percent Na2CO3 in impure base sample??? I did my calculations but it somehow...

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Question

Chemistry

How to calculate the weightpercent Na2CO3 in impure base sample???

I did my calculations but itsomehow doesnt make sense

First we find the moles of HCl

=0.1M HCl x volume of HCl used to titrate

       =0.1M x 10.5mL HCl

       =1.05 mol HCl

The ratio between Na2CO3 and Hcl is 1:2

Moles Na2CO3

= moles of HCl/2

=1.05mol HCl/2

=0.525mol Na2CO3

Mass Na2CO3

= moles of Na2CO3 x 105.9906 g/mol

       =0.525 mol Na2CO3 x105.9906 g/mol

       =55.65 g

%    = mass of Na2CO3 x100/mass of sample fromthe impure solid

       =55.65g x 100/ 0.1328g =41905.1205 ???

What did I do wrong??? (do I need to include the fact that thatthe impure base was first mixed with 25 mL of distilled water???The HCl used is 0.1M for titrate to its endpoint)

Impure base

1

Mass (g)

0.1328

Trial 1 volume of HCl used in titration (mL)

10.5

Trial 2 /2nd titration(after boiling) : volume of HCl used intitration (mL)

3

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