How much heat is released when 28.0 g of lithium metal reacts as shown below? (Answer...

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Chemistry

How much heat is released when 28.0 g of lithium metal reacts asshown below? (Answer should come out to 448 kJ)

2 Li (s) + 2 H2O (ℓ) → 2 LiOH (s) + H2 (g)ΔHº = −222 kJ

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3.6 Ratings (266 Votes)

ΔHº = −ve = exothermic reaction = heat will be released

Molar mass of Li = 6.94 g/mol

2 Li (s) + 2 H2O (ℓ) → 2 LiOH (s) + H2 (g)        ΔHº = −222 kJ

2 mol                                                           222 kJ heat is released

2 x 6.94 g = 13.88 g                                      222 kJ heat is released

28 g                                                                        ?

Then,

                     ? = ( 28 g/ 13.88 g) x 222 kJ heat is released

                        = 448 kJ heat is released

Therefore,

448 kJ heat is released when 28.0 g of lithium metal reacts.


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