1) The mass of NaCl required to prepare 1.0 L of 0.240 M NaCl =
(0.240 mol/L)(1.0 L) (58.44 g/mol) = 14.02 g
2) The mass of CuSO4 required to prepare 250 mL of
0.135 M CuSO4
                                                              Â
= (0.135 mol/L)(0.250 L) (159.61 g/mol) = 5.386 g
CuSO4
3) The mass of CH3OH required to prepare 500 mL of
0.370 M CH3OH
                                                              Â
= (0.370 mol/L)(0.5 L) (32.0 g/mol) = 5.92 g
CH3OH
