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How many moles of NH3 can be produced when 11.00 mol H2 react with 5.00 mol...

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Chemistry

How many moles of NH3 can be produced when 11.00 mol H2 reactwith 5.00 mol N2?

_________mol NH3

How many moles of each reactant are left over? Note that atleast one must disappear.

______mol H2 remain

_______mol N2 remain

Answer & Explanation Solved by verified expert
3.9 Ratings (421 Votes)

N2    +   3 H2 -------------------> 2 NH3

1mol      3 mol                         2 mol

5 mol     11 mol                             ?

here limiting reagent is H2. so NH3 formed based on that.

3 mol H2 -------------- 2 mol NH3

11 mol H2 -------------- ?? NH3

moles of NH3 produced = 11 x 2 / 3

                                          = 7.33 mol NH3

we need only 3.67 mol of N2. here we have 5 mol of N2 . so N2 is left over

moles of N2 remain = 5 - 3.67 = 1.33 mol N2

moles of H2 = 0 . it all consumed
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