How many molecules are contained in a 7.10-g sample of dimethylmercury? What is the percentage of mercury...

4.2 Ratings (695 Votes)

Dimethylmercury is (CH3)₂Hg

Molar mass of (CH3)₂Hg = 230.66 g

mass = 7.1 g

number of moles = mass /molar mass

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â =7.1/230.66

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â =0.031 mol

Number of molecules = Avogadro's number * number of moles

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = (6.022*10^23)*(0.031)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â =1.854*10^22 molecules.

Answer: 1.854*10^22 molecules

number of moles of Hg in compound = 0.031 mol

molar mass of Hg = 200.59gm

mass of Hg = number of moles * molar mass of Hg

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â =0.031*200.59

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â =6.22 gm

percentage of mercury = mass of mercury *100 / total mass

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 6.22*100/7.1

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 87.6 %

Answer: 87.6 %

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