How many microliters of a 872.0 ppm Co2 stock solution are required to prepare 19.00 mL...

4.1 Ratings (428 Votes)

According to law of dilutionÂ Â MV = M'V'

Where M = Molarity of stock = 872.0 ppm = 872.0 mg/L

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 872.0x10^-3 g/10⁶ Î¼L

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 872.0x10^-9 g/Î¼L

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 872.0 ng/Î¼L

V = Volume of the stock = ?

M' = Molarity of dilute solution = 13.0 ng/Î¼L

V' = Volume of the dilute solution = 19.00 mL

Plug the values we get , V = ( M'V') / M

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = (13.0x19.0) / 872.0

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.28 mL

Therefore the volume of stock solution required is 0.28 mL

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