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how many kj of heat are absorbed when 455g of water at 80.0C are heated to...

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Chemistry

how many kj of heat are absorbed when 455g of water at 80.0C areheated to 100.0C and then completely evaporated at thistempertature? The Specific heat of water 4.184j/C, g and the molarheat of evaporation for water is 40.7kJ/mol.

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3.8 Ratings (357 Votes)

Answer - Given, mass of water = 455 g , ti = 80.0oC, tf = 100.0oC

Specific heat of water = 4.184 J/goC , ∆Hvap = 40.7 kJ/mol

Moles of water = 455 g / 18.016 g.mol-1

                         = 25.3 moles

We know the formula for the heat

q1 = m*C*∆t

    = 455 g * 4.184 J/goC * (100.0-80.0)oC

    = 38074.4 J

Now heat from the 100.0 to 100.0oC

q2 = m*∆Hvap

      = 18518.5 J

So, total heat absorbed = q1 + q2

                                     = 38074.4 + 18518.5

                                     = 56593 J

                             = 56.59 kJ
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