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How many grams of copper be deposited at the cathode of an electrolysis cell if an...

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Chemistry

How many grams of copper be deposited at the cathode of anelectrolysis cell if an electric current of 15 mA is applied for1.0 h through an aqueous solution containing excess Cu2+ ions?Assume the process is 100°0 efficient.

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3.7 Ratings (693 Votes)

According to Faraday's first law , W = (ECT) / 96500

Where W = mass of metal deposited = ?

           E = Equivalent weight of Cu = 63.54 / 2

                                                    = 31.77

           C = current = 15 mA = 15 x10-3 A

           t = time taken = 1.0 h

                                = 1.0x60x60 s

                                = 3600 s

Plug the values we get

W = ( 31.77 x 15x10-3 x 3600 ) / 96500

    = 0.018 g

Therefore the mass of copper deposited is 0.018 g
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