How do you find the domain of:
f(g)= 5x^2+4
f(g)= 3x; -2f(g)= (1) / 3x-6f(g)= (x+2) / x^2-1f(g)= x^4 / x^2+x-6f(g)= sqrt (x+1)f(g)= sqrt (x^2+9)
f(g)= (1) / 3x-6
f(g)= (x+2) / x^2-1
f(g)= x^4 / x^2+x-6
f(g)= sqrt (x+1)
f(g)= sqrt (x^2+9)
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