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Here is a census for an apportionment problem in a hypothetical country comprised of four states....

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Basic Math

Here is a census for an apportionment problem in a hypotheticalcountry comprised of four states. • State of Ambivalence: 8,000; •State of Boredom: 9,000; • State of Confusion: 24,000; • State ofDepression: 59,000. (100,000 total) Assume that the house has h =10 seats to apportion to these four states. What apportionment isdetermined by the method of: Hamilton, Adam, Jefferson,Webster.

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4.5 Ratings (923 Votes)

The standard divisor is SD= Total population/Number of seats = 1,00,000/10=10,000

The standard quota id SQ = State population/Standard Devisor

Hamilton:

State Ambivalence Boredom Confusion Depression Total
Population 8000 9000 24000 59000 1,00,000
Standard Quota 0.8(2) 0.9(1) 2.4(4) 5.9(1) 10
Lower Quota 0 0 2 5 7
Final Allocation 1 1 2 6 10

Jefferson’s method:

State Ambivalence Boredom Confusion Depression Total
Population 8000 9000 24000 59000 1,00,000
d=8300 0.96 1.08 2.89 7.11 12.05
Lower Quota 0 1 2 7 10

Adam's method:

State Ambivalence Boredom Confusion Depression Total
Population 8000 9000 24000 59000 100000
d=11875 0.67 0.76 2.02 4.97 8.421
Upper Quota 1 1 3 5 10

Webster's method:

State Ambivalence Boredom Confusion Depression Total
Population 8000 9000 24000 59000 100000
d=10000 0.80 0.90 2.40 5.90 10
Rounded Quota 1 1 2 6 10
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