Here are four problems (5 pts each) involving the calculation of DG°' for metabolic reactions we...

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Chemistry

Here are four problems (5 pts each) involving the calculation ofDG°' for metabolic reactions we have discussed, based onexperimentally determined redox potentials. Calculate theDG°' for each reaction using the equation DG°' =-nFDE0' and the values forE0' given in Table 1. Showyour work and circle your answer.

Table 1. Reduction potentials for reductionhalf reactions:

1/2 O2 + 2H+ + 2e- ®H2O                                             E0' = +0.82 V

fumarate + 2H+ + 2e- ®succinate                                 E0' = +0.03 V

oxaloacetate + 2H+ + 2e- ®malate                               E0' = -0.17 V

pyruvate + 2H+ + 2e- ®lactate                                    E0' = -0.19 V

a-ketoglutarate + CO2 + 2H+ +2e- ® isocitrate             E0' = -0.38 V

FAD + 2H+ + 2e- ®FADH2                                           E0' = -0.22 V

NAD+ + 2H+ + 2e- ®NADH +H+                                  E0' = -0.32 V

CoQ + 2H+ + 2e- ®CoQH2                                           E0' = +0.06 V

Problem 3. malate + NAD+ ®oxaloacetate + NADH + H+

Problem 4. FADH2 + CoQ ® FAD +CoQH2

Answer & Explanation Solved by verified expert
3.6 Ratings (672 Votes)

malate + NAD+ -------------------> oxaloacetate + NADH + H+

malate -----------------> oxaloacetate + 2H+ + 2e-           E0 = 0.17V

NAD+ + 2H+ + 2e- ---------> NADH + H+                                    E0' = -0.32 V

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malate + NAD+ -------------------> oxaloacetate + NADH + H+     E0cell= -0.15V

DG°' = -nFDE0'

        = -2*96500*-0.15   = 28950J

FADH2 + CoQ ------------> FAD + CoQH2

FADH2   ------------> FAD + 2H+ + 2e-      E0 = 0.22V

CoQ + 2H+ + 2e- -----------> CoQH2        E0' = +0.06 V

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FADH2 + CoQ ------------> FAD + CoQH2   E0cell =0.28V

DG°' = -nFDE0'

        = -2*96500*0.28 = -54040J


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