Haskell Map and Filter 6. Let f1 = filter ( x -> x > 0) and f2...

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Haskell

Map and Filter

6. Let f1 = filter ( x -> x > 0) and f2 = filter (x-> x < 10), and let nbrFilter g x = length (filter g x).

a. Rewrite f1(f2[-5..15]) so that it uses function compositionto apply just one function to the list.

b. Rewrite the nbrFilter function definition to have theform

nbrFilter g = function composition involving length and filter …and leaving out x.

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Given Functions f1x This filter will pass the values which are more than 0 f2x This filter will pass the values which are less than    See Answer
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