Given the function g(x) = 8x^33 + 36x^2 + 48x, find the first derivative, g'(x)=______________Notice...

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Given the function g(x) = 8x^33 + 36x^2 + 48x, find the first derivative, g'(x)=______________Notice that g'(x) = 0 when x = -2, that is, g'( - 2) = 0.Now, we want to know whether there is a local minimum or local maximum at x = -2, so we will use the second derivative test.Find the second derivative, g''(x).g''(x)=____________Evaluate g''(-2).g''( - 2) =_______________Based on the sign of this number, does this mean the graph of g(x) is concave up or concave down at x= - 2?At x = 2 the graph of g(x) is ____________Based on the concavity of g(x) at x = 2, does this mean that there is a local minimum or local maximum at x= - 2?At x = - 2 there is a ____________

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