Given:
Molar Concentration of Fe(NO3)3 is 0.2
Molar concentration of NaSCN is 0.001
Volume of Fe(NO3)3 is 10.00 ml (in 0.1 M HNO3)
Volume of NaSCN is 2.00 ml (in 0.1 M HNO3)
10.00 ml Fe(NO3)3 + 2.00ml NaSCN + 13.00 ml HNO3= 25 mL
Calculate:
a) Moles of SCN-
b) [SCN-] (25.0 ml)
c) [FeNCS2+]
