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Given: Molar Concentration of Fe(NO3)3 is 0.2 Molar concentration of NaSCN is 0.001 Volume of Fe(NO3)3 is 10.00...

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Chemistry

Given:
Molar Concentration of Fe(NO3)3 is 0.2
Molar concentration of NaSCN is 0.001
Volume of Fe(NO3)3 is 10.00 ml (in 0.1 M HNO3)
Volume of NaSCN is 2.00 ml (in 0.1 M HNO3)
10.00 ml Fe(NO3)3 + 2.00ml NaSCN + 13.00 ml HNO3= 25 mL

Calculate:
a) Moles of SCN-
b) [SCN-] (25.0 ml)
c) [FeNCS2+]

Answer & Explanation Solved by verified expert
4.2 Ratings (745 Votes)
You cant do this problem unless you know the equilibrium concentration of the complex which you havent given The initial moles used are Moles of Fe 10 mL 001 L 001 L x 02 molL 2 x 103 mol    See Answer
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