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Given a 2.00 μF capacitor, a 5.00 μF capacitor, and a 6.50 V battery, find the...

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Physics

Given a 2.00 μF capacitor, a 5.00 μFcapacitor, and a 6.50 V battery, find the charge on each capacitorif you connect them in the following ways.

(a) in series across the battery

2.00 μF capacitor...μC
5.00 μF capacitor... μC


(b) in parallel across the battery

2.00 μF capacitor...μC
5.00 μF capacitor...μC

Answer & Explanation Solved by verified expert
4.4 Ratings (625 Votes)

Given that

C1 = 2.00 * 10^-6 F

C2 = 5.00 * 10^-6 F

voltage V = 6.50 V

The equivalent capacitance is

        1/C = 1/C1 + 1/C2

         1/C = 1/( 2.00*10^-6 F) + 1/(5.0*10^-6 F)

           C =1.42857*10^-6 F

So the charge across each capacitance (2.00 µF and 5.00 µF) is

         Q = CV

             = (1.42857*10^-6 F)(6.50 V)

             = 9.2857*10^-6 C

            = 9.2857 μC

b)

The charge across capacitor 2.75 µF is

         q1 =C1V = (2.00*10^-6F)(6.50 V)

                         = 13*10^-6 C

                          = 13.0 μC

The charge across capacitor 5.00 µF is

        q2 = C2V = (5.00 * 10^-6 F)(6.50 V)

                         = 32.510^-6 C

                         = 32.5 μC

I hope help you !!
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