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Given 319.5 g of hot tea at 72.0 ∘C, what mass of ice at 0...

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Chemistry

Given 319.5 g of hot tea at 72.0 ∘C, what mass of ice at 0 ∘Cmust be added to obtain iced tea at 13.5 ∘C? The specific heat ofthe tea is 4.18 J/(g⋅∘C), and ΔHfusion for ice is +6.01kJ/mol.

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The formula for these types of problems is M1 x C1 x dT1 M2 xC2 x dT1M1 is mass for iced tea M2 is massfor the ice cubeC1 is specific heat capacity of tea 418JgoCC2 is specific heat of ice 209 JgCdT is temperature difference for the iced tea its 595    See Answer
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