Gas Laws Units in Gas Law Problems One problem associated with gas law problems is unit agreement. It...

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Chemistry

Gas Laws

Units in Gas Law Problems

One problem associated with gas law problems is unit agreement.It is important that pressure, volume and temperature units matchor agree within a problem. Solve 1-4 using the factor-label method.Problems 5 and 6 are done without factor-label.

1. Convert 1.52 atm to kPa 2. Convert 85 kPa to mmHg

3. Convert 156.3 mmHg to atm 4. Convert 950 torr to kPa

5. Convert -250.0 °C to K 6. Convert 253 K to °C

Boyle’s Law

7. Equation for Boyle’s Law:

8. A gas occupies 12.3 L at 825.7 mmHg. What will the pressurebe when the volume is 75 L?

9. A gas occupies 25 L at 2.5 atm. What is the volume if thepressure changes to 1.5 atm?

10. You have 50 L of CO2gas at standard temperature and pressure (STP). What would need tobe done to the pressure to cut the volume of gas in half?

Charles’ Law

11. Equation for Charles’ Law:

12. How do these two factors relate to each other?

13. What does temperature actually measure?

14. At 27.8 °C, a gas occupies 1500 m. What volume will it haveat 100.0 °C?

15. What temperature (in K) must a gasbe if it occupied 1.396 L at 72.3 °C and now occupies 1.044 L?

Gay-Lussac’s Law

16. Equation for Charles’ Law:

17. A gas cylinder contains nitrogen gas at 10-atm pressure anda temperature of 20ËšC. The cylinder is left in the sun, and thetemperature of the gas increases to 50ËšC. What is the pressure inthe cylinder?

18. A bike tire has a volume of 0.850L at a pressure of 40 psiand 0ËšC. What will be the pressure of the tire at 35ËšC?

19. An aerosol can has a fixed volume of gas at 4.0-atm ofpressure and room temperature (25ËšC). If the pressure inside thecan reaches 5.9-atm the can will explode. The can is thrown into afire that is 400ËšC. Will the can explode? Show all calculations tosupport your answer.

Answer & Explanation Solved by verified expert
3.8 Ratings (402 Votes)
1 152 atm 152 atm 1 x 101325 kpa 1 atm 154014 kpa 2 85 kpa 85 kpa 1 x 75 mm Hg 1 kpa 6375 mm Hg 3 1563 mm Hg 1563 mm Hg 1 x 1 atm 760 mm Hg 02057 atm 4 950 Torr 950 Torr 1 x 1 kpa 75 Torr 1267 kpa 5 250 0C 250 273 K 523 K 6 253 K 253 273 0C 20 0C 7 Boyles law equation PV constant or p1V1 P2V2 at constant temperature 8 Let P2 be the pressure at volume V2 75 L    See Answer
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