From t = 0 to t = 4.66 min, a man stands still, and from...

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Physics

From t = 0 to t = 4.66 min, a man stands still, and from t =4.66 min to t = 9.32 min, he walks briskly in a straight line at aconstant speed of 1.66 m/s. What are (a) his average velocity vavgand (b) his average acceleration aavg in the time interval 1.00 minto 5.66 min? What are (c) vavg and (d) aavg in the time interval2.00 min to 6.66 min?

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Average Velocity is given by Vavg dxdt xf xitf ti Average acceleration is given by aavg dVdt Vf Vitf ti Part A for this part time interval dt 566 100 466 min 1 min 60    See Answer
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