For this problem, carry at least four digits after the decimalin your calculations. Answers may vary slightly due torounding.
A random sample of 5535 physicians in Colorado showed that 3386provided at least some charity care (i.e., treated poor people atno cost).
(a) Let p represent the proportion of all Coloradophysicians who provide some charity care. Find a point estimate forp. (Round your answer to four decimal places.)
(b) Find a 99% confidence interval for p. (Round youranswers to three decimal places.)
| lower limit    | |
| upper limit    | |
Give a brief explanation of the meaning of your answer in thecontext of this problem.
99% of the confidence intervals created using this method wouldinclude the true proportion of Colorado physicians providing atleast some charity care.
1% of all confidence intervals would include the true proportionof Colorado physicians providing at least some charity care.
99% of all confidence intervals would include the trueproportion of Colorado physicians providing at least some charitycare.
1% of the confidence intervals created using this method wouldinclude the true proportion of Colorado physicians providing atleast some charity care.
(c) Is the normal approximation to the binomial justified in thisproblem? Explain.
No; np > 5 and nq < 5.Yes; np< 5 and nq < 5.    No;np < 5 and nq > 5.Yes; np > 5and nq > 5
