For this problem, carry at least four digits after the decimalin your calculations. Answers may vary slightly due torounding.

In a marketing survey, a random sample of 1010 supermarket shoppersrevealed that 266 always stock up on an item when they find thatitem at a real bargain price.

(a)

Let p represent the proportion of all supermarketshoppers who always stock up on an item when they find a realbargain. Find a point estimate for p. (Enter a number.Round your answer to four decimal places.)

(b)

Find a 95% confidence interval for p. (For each answer,enter a number. Round your answers to three decimal places.)
lower limit     
upper limit     

Give a brief explanation of the meaning of the interval.

5% of all confidence intervals would include the true proportionof shoppers who stock up on bargains

95% of the confidence intervals created using this method wouldinclude the true proportion of shoppers who stock up onbargains.   

5% of the confidence intervals created using this method wouldinclude the true proportion of shoppers who stock up onbargains.

95% of all confidence intervals would include the trueproportion of shoppers who stock up on bargains.

(c)

As a news writer, how would you report the survey results on thepercentage of supermarket shoppers who stock up on items when theyfind the item is a real bargain?

Report the margin of error.

Report p?.  

  Report p? along with the margin oferror.

Report the confidence interval.

What is the margin of error based on a 95% confidence interval?(Enter a number. Round your answer to three decimal places.)