For the reactions shown below, we added 2.25 mL of 0.0450 M HCl to a test...

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Chemistry

For the reactions shown below, we added 2.25 mL of 0.0450M HCl to a test tube containing one of the two cations(Ag⁺ or Pb²⁺) and recovered 0.0141 g ofprecipitate.
AgNO₃(aq) + HCl(aq) â†’AgCl(s) + HNO₃(aq)
Pb(NO₃)₂(aq) + 2 HCl(aq) â†’PbCl₂(s) + 2 HNO₃(aq)
How much precipitate in moles would be recovered theoreticallyif the ion was Ag⁺? (Enter an unrounded value. Use atleast one more digit than given.)
mol

How much precipitate in moles would be recovered theoretically ifthe ion was Pb²⁺? (Enter an unrounded value. Use atleast one more digit than given.)
mol

How much precipitate in grams would be recovered theoretically ifthe ion was Ag⁺?
g

How much precipitate in grams would be recovered theoretically ifthe ion was Pb²⁺?
g

Based on the precipitate amount recovered, which of the two ionswas in the unknown?
Ag⁺
Pb²⁺Â Â

Answer & Explanation Solved by verified expert

3.9 Ratings (800 Votes)

Assume that Ag and Cl react completelyAg Cl AgCl recovered precipitate 00141gms If this is divided with the molar mass of Agcl 14332units of molar mass is gmmol you would obtain experimental grams of precipitate recovered when Ag ion is used 0014114332 983812 105 moles To find experimental gms See Answer

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