For the reaction shown below, Kp = 0.148 at 37

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Chemistry

For the reaction shown below, K_p = 0.148 at 37

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4.0 Ratings (644 Votes)

CO(g) + Br₂(g) <------------------------> COBr₂(g)

1.81 Â Â Â Â Â 1 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 1.59 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â at initial

1.81-xÂ Â Â 1-xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 1.59 +xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â at equilibrium

Kp = [1.59 +x] /[1.81-x ] [1-x]

0.148 = [1.59 +x] /[1.81-x ] [1-x]

x= 0.03

P_CO,eq (atm) =1.81-0.03=1.78

P_Br2,eq (atm) =1-x= 0.97

P_COBr2,eq (atm)= 1.59 +x= 1.62

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For the reaction shown below, Kp = 0.148 at 37

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For the reaction shown below, Kp = 0.148 at 37

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For the reaction shown below, K_p = 0.148 at 37