CO(g) + Br2(g) <------------------------>
COBr2(g)
1.81 Â Â Â Â Â 1
                                      Â
1.59
                 Â
at initial
1.81-x  Â
1-x                                          Â
1.59
+x              Â
at equilibrium
Kp = [1.59 +x] /[1.81-x ] [1-x]
0.148 = [1.59 +x] /[1.81-x ] [1-x]
x= 0.03
PCO,eq (atm) =1.81-0.03=1.78
PBr2,eq (atm) =1-x= 0.97
PCOBr2,eq (atm)= 1.59 +x= 1.62
