For the highest temperature, is more of the intensity (area of the intensity vs. wavelength graph)...

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Physics

For the highest temperature, is more of the intensity (area ofthe intensity vs. wavelength graph) in the visible part of thespectrum or in the infrared part of the spectrum? How could a lightbulb be made more efficient so it puts out more light in thevisible?

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Amazingly all matter in the universe gives off light at everywavelength from gamma rays to radio but we give off a lot more ofcertain kinds of light based on our temperature This is calledblackbody radiation and a graph of how much light comes in at eachtemperature is called an objects blackbody curve The blackbodycurve peaks at different wavelengths    See Answer
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