For the following reaction, Kc = 255 at 1000 K. CO (g) + Cl2 (g) â‡Œ...

3.9 Ratings (493 Votes)

Given :

[CO]=0.1550 M and [Cl2] = 0.178 MÂ Â Â Â Â Â Â Â at T = 1000 K.

Kc = 255

Lets use ICE chart.

CO (g) +Â Â Â Â Â Â Â Â Â Â Cl2 (g) â‡Œ COCl2 (g)

IÂ Â Â Â Â Â Â Â Â Â 0.1550 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.178 Â Â Â Â Â Â Â Â Â Â Â Â Â 0

CÂ Â Â Â Â Â Â Â Â -xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â -xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â +x

EÂ Â Â Â Â Â Â Â Â (0.1550-x)Â Â Â Â Â Â (0.178-x)Â Â Â Â Â Â Â Â x

Kc = [COCl2]/[CO][Cl2]

255 = x / ( 0.1550-x) ( 0.178-x)

255 = x/ (x² â€“ 0.333x + 0.02759 )

255 x² â€“ 84.915x + 7.035 = x

255 x² â€“ 85.915x + 7.035 = 0

We use quadratic formula to solve this problem

By using quadratic formula we get

x = 0.14 = [COCl2] = 0.14 M

[CO]= 0.1550 â€“ 0.140 = 0.015 M

[Cl2]= 0.178-0.140 = 0.038 M

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