For the balanced equation shown below, if 98.0 grams of C2H3Br3 were reacted with 62.2 grams...

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Chemistry

For the balanced equation shown below, if 98.0 grams of C2H3Br3were reacted with 62.2 grams of O2, how many grams of Br2 would beproduced? 4C2H3Br3+11O2=8CO2+6H2P+6Br2

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3.8 Ratings (377 Votes)

4C2H3Br3 +   11O2 --------------------------->    8CO2   +     6H2P +     6Br2

1066.8 g          352 g                                                                             479.4g

98.0 g               62.2 g                                                                            ?

1066.8 g C2H3Br3   -----------------------> 352 g O2

98 .0 g C2H3Br3 -------------------------> 352 x 98 / 1066.8 = 32.33 g O2

we need only 32.33 g O2 . but we have 62.2 g O2 so it is excess reagent .

so limiting regaent is C2H3Br2.

1066.8 g C2H3Br3 --------------------------> 479.4 g Br2

98 g   C2H3Br3 -------------------------------> 479.4 x 98 / 1066.8 = 44.0 g

mass of Br2 formed = 44.0 g


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