For each of the following integrals predict whether the improper integral converges In this case...

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For each of the following integrals predict whether the improper integral converges In this case we re looking for a casual comparison that we would use to guide our search for a comparison integral that would prove convergence or divergence For example for 36 x 1 For convergence enter converges or diverges Si dx for large x the integrand looks like 1 x so we predict the integral diverges x 6 S8 da for larger the integrand looks like 8 8 for large x the integrand looks like for large x the integrand looks like S z7 dx 7 de 00 8 Six 1 e 6 1 8x 6 1 d for large x the integrand looks like 113 so we predict the integral converges so we predict the integral diverges so we predict the integral converges so we predict the integral diverges Hint Use the largest powers of x or e without coefficient in the numerator and denominator to determine your comparison

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For each of the following integrals predict whether the improper integral converges In this case we re looking for a casual comparison that we would use to guide our search for a comparison integral that would prove convergence or divergence For example for 36 x 1 For convergence enter converges or diverges Si dx for large x the integrand looks like 1 x so we predict the integral diverges x 6 S8 da for larger the integrand looks like 8 8 for large x the integrand looks like for large x the integrand looks like S z7 dx 7 de 00 8 Six 1 e 6 1 8x 6 1 d for large x the integrand looks like 113 so we predict the integral converges so we predict the integral diverges so we predict the integral converges so we predict the integral diverges Hint Use the largest powers of x or e without coefficient in the numerator and denominator to determine your comparison

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