(1) Keq = [NH3]^2/[N2][H2]^3
                         Â
N2Â Â Â Â Â Â Â Â Â
+Â Â Â Â
     3H2   Â
------------->Â Â Â 2NH3
initial                    1                         3                             Â
0
change           Â
-0.01925Â Â Â Â Â Â Â Â Â Â
-0.05775Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.03885
equilibrium    Â
(1-0.01925)Â Â Â Â Â
(3-0.05775)Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0.03885
Feed in the equation,
Keq = (0.03885)^2/(1-0.01925)(3-0.05775)^3
       = 6.04 x 10^-5
(2) Total moles = 1 + 3 + 0.5 = 4.5
total presure of the system = 4.5 x 0.0821 x 673/22.4 = 11.1
atm
P(N2) =
