For 200.0 mL of a buffer solution that is 0.2975 M in CH3CH2NH2 and 0.2730 M...

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Chemistry

For 200.0 mL of a buffer solution that is 0.2975 M in CH3CH2NH2and 0.2730 M in CH3CH2NH3Cl, calculate the initial pH and the finalpH after adding 0.0100 mol of NaOH(Kb=6.46⋅10−4).

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3.9 Ratings (606 Votes)
Given This is buffer so we use Henderson equation pOH pkb log conjugate acid conjugate base pOH log kb log conjugate acid conjugate base pOH log 646 E4 log 02730 02975 315 pH    See Answer
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