Flag this Question Question 1 1 pts Calculate the molarity of 2.45 mol CaCl2 in 0.3 L solution. 8.16...

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Chemistry

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Question 1 1 pts

Calculate the molarity of 2.45 mol CaCl2 in 0.3 Lsolution.

8.16 M
0.735 M
0.122 M
5.42 M

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Question 2 1 pts

What are the products of this acid-base reaction: HI(aq) +Ba(OH)2(aq)?

BaI2 and H2O
BaH2 and I(OH)2
BaO and H2O
BaI2 and 2OH-

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Question 3 1 pts

Write the complete ionic equation for:Pb(NO3)2(aq) + 2KCl(aq)-->PbCl2(s) + 2KNO3(aq)

Pb2+(aq) + 2NO3-(aq) + 2K+(aq) + 2Cl-(aq) -> PbCl2(s) +2K+(aq) + 2NO3-(aq)
Pb2+(aq) + 2NO3-(aq) + 2K+(aq) + 2Cl-(aq) -> Pb2+(aq) +2NO3-(aq) + 2KCl(aq)
Pb2+(aq) + 2NO3-(aq) + 2K+(aq) + 2Cl-(aq) -> Pb2+(aq) +2Cl-(aq) + 2KNO3-(aq)
Pb2+(aq) + 2NO3-(aq) + 2K+(aq) + 2Cl-(aq) -> Pb2+(aq) +2Cl-(aq) + 2K+(aq) + 2NO3-(aq)

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Question 4 1 pts

What is the molarity of CO32- in 0.24 MAl2(CO3)3?

0.72 M
0.48
0.24 M
0.08 M

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Question 5 1 pts

If 430 mL of a 5.5 M glucose solution is diluted to 1500 mL,what is the molarity of the diluted solution?

1.58 M
2.0 M
0.13 M
3.2 M

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Question 6 1 pts

To what volume would you dilute 35 mL of a 9.5 M stock HClsolution to obtain a 1.4 M HCl solution?

238 mL
530 mL
300 mL
425 mL

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Question 7 1 pts

What volume of 2.5 M glucose solution contains 0.78 mols ofglucose?

0.312 L
0.631 L
0.095 L
2.5 L

Answer & Explanation Solved by verified expert
3.6 Ratings (461 Votes)
1 Moles of CaCL2 245Volume of solution 03 LMolarity Moles Volume L 245 03 816 M2 products of this acidbase reaction HIaq BaOH2aq are2HIaq BaOH2aq 2H2Ol BaI2aq3 PbNO32aq 2KClaq PbCl2s 2KNO3aqThe    See Answer
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