Five persons A, B, C, D, and E are seated at random in a row ofseats numbered 1, 2, 3, 4, and 5.
a) Find the probability that A is seated on seat 2.
b) FInd the probability that A and B are not seated with eachother.
a) P(A is seated on seat 2) = 4!/5! = 0.2
b) P(A and B are not seated with each other) = 1 - P(A and B are seated with each other)
= 1 - (4! * 2!)/5!
= 1 - 0.4 = 0.6
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