Find the wavelength (in nm) of a photon whose energy is 9.00 × 10-19 J.

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Physics

Find the wavelength (in nm) of a photon whose energy is 9.00 ×10-19 J.

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4.3 Ratings (932 Votes)

Given data

                 Energy(E)=9.00*10^(-19)

                 We know(E)=hf   ( f=c/lamda)

                 So      E=hc/lamda

                 Lamda =hc/E

                             =(6.63)*^10(-34)*(3)*10(^8)/(9.00)*10^(-19)

                              =(6.63)*(3)*(10)^(-26)(/9.00)*(10)^(-19)

                              =(19.89/9.00)*10(-7)

                              =2.21*10(-7) meters

                               =221 nm


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