Find the value of the standard normal random variable zz , called z0z0 such that: (a) P(z?z0)=0.9999P(z?z0)=0.9999 z0=z0= (b) P(?z0?z?z0)=0.922P(?z0?z?z0)=0.922 z0=z0= (c) P(?z0?z?z0)=0.3954P(?z0?z?z0)=0.3954 z0=z0= (d) P(z?z0)=0.4497P(z?z0)=0.4497 z0=z0= (e) P(?z0?z?0)=0.3225P(?z0?z?0)=0.3225 z0=z0= (f) P(?1.66?z?z0)=0.5474P(?1.66?z?z0)=0.5474 z0=z0=

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Find the value of the standard normal random variablezz , called z0z0 such that:

(a)P(z?z0)=0.9999P(z?z0)=0.9999
z0=z0=

(b)P(?z0?z?z0)=0.922P(?z0?z?z0)=0.922
z0=z0=

(c)P(?z0?z?z0)=0.3954P(?z0?z?z0)=0.3954
z0=z0=

(d)P(z?z0)=0.4497P(z?z0)=0.4497
z0=z0=

(e)P(?z0?z?0)=0.3225P(?z0?z?0)=0.3225
z0=z0=

(f)P(?1.66?z?z0)=0.5474P(?1.66?z?z0)=0.5474
z0=z0=

Answer & Explanation Solved by verified expert
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solution a P z z0 09999Pz z0 109999 00001 Pz z0 00001 From tables z0 372 b P z0 z z0 922 P z z0 P z z0 P z z0 P z z0 P z    See Answer
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