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Find the value of polynomial 5x–8x^2+3 at the points(i) x=–5(ii)x=0

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Question

Basic Math

Find the value of polynomial 5x–8x^2+3 at the points

(i) x=–5

(ii)x=0

Answer & Explanation Solved by verified expert
3.6 Ratings (456 Votes)

Solution:

The given polynomial is,

5x–8x^2+3 .... (A) 

(i)To find the value at point x=–5

On substituting x=–5 in the polynomial given by (A) we get, 

=5(–5)–8(–5)^2+3

=–25–8(25)+3

=–25–200+3

=–225+3

=–222

 

(ii) Similarly, we can find the value of polynomial (A) at point x=0.

Substitute x=0 in the polynomial given by (A), 

we have, 

=5(0)–8(0)^2+3

=0–0+3

=3

The value of polynomial 5x–8x^2+3 at

(i) x=–5 is –222. 

(ii) x= 0 is 3. 
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