Find the equation of the hyperbola with vertices (1,6) and (1,0) and foci (1,9) and (1, -3). Select the correct answer below: (y-3)/27 - (x+1)/9 = 1(y-3)/9 -(x-1)/27 = 1(x-1)/9 - (y-3)/27 = 1(x+1)/9 - (y+3)/27 = 1(y+3)/27 - (x+1)/9 = 1(x+1)/9 - (y-3)/27 = 1
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