Explain and solve the following physics question. An alpha particle with kinetic energy 14.0 MeV makes...

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Physics

Explain and solve the following physics question.
An alpha particle with kinetic energy 14.0 MeV makes a collisionwith lead nucleus, but it is not \"aimed\" at the center of the leadnucleus, and has an initial nonzero angular momentum (with respectto the stationary lead nucleus) of magnitudeL=p0b, where p0 is themagnitude of the initial momentum of the alpha particle andb=1.20Ã—10^âˆ’12 m . (Assume that the lead nucleusremains stationary and that it may be treated as a point charge.The atomic number of lead is 82. The alpha particle is a heliumnucleus, with atomic number 2.)
1. What is the distance of closest approach? Find r.(meters)
2. Repeat for b =1.30Ã—10^âˆ’13 m. Find r.(meters)
3. Repeat for b =1.30Ã—10^âˆ’14 m. (meters)

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4.3 Ratings (518 Votes)

The trajectory of the Alpha particle is a hyperbola as it isrepelled by the positive charge on Lead nucleusFor an axis through the Lead nucleus perpendicular to See Answer

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