Experiment shows that the reaction 6I−(aq) + BrO3 −(aq) +6H+(aq) ⟶ 3I2 (aq) + Br−(aq) + 3H2O(l) obeys this rate law: rate =k[I- ][BrO3 ][H+] 2 .
(a) What is the reaction order in each reactant and the overallreaction order?
(b)By what factor does the rate change if [I−] and [BrO3 −] aretripled and [H+] is doubled?