Ethylamine, C2H5NH2, is a weak base. 250.0 mL of a 0.160 M C2H5NH2  solution is titrated with 0.500...

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Chemistry

Ethylamine, C2H5NH2,is a weak base. 250.0 mL of a 0.160 M C2H5NH2  solutionis titrated with 0.500 M HCl (aq). Find the KbKbvalue in a lecture slide. Calculate the pH at the followingpoints.

  1. 30. mL of HCl solutionadded.
  2. At the halfwaypoint.
  3. At the equivalence point.Verify any assumption you made.
  4. 90. mL of HCl solutionadded.

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3.6 Ratings (372 Votes)
ethylamine Kb 63104 pKb 32 millimoles of ethylamine 250 x 016 40 a 30 mL titrant added millimoles of HCl 30 x 05 15 C2H5NH2 HCl    See Answer
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