ErmTR is an enzyme found in S.pyogenes strains that are resistant to erythromycin. While workingin the lab one afternoon you discover a small molecule (C23) thatinhibits the activity of ermTR. To assess the type of inhibitor youdiscovered, you set up reactions with 6 different concentrations oferythromycin and varying amounts of the C23 small molecule youdiscovered. To each reaction you add 2 x 10-12 mol of ermTR (totalreaction volume: 15 mL) and measure the initial velocities, Vo, byspectrophotometry. You obtained the following data:

Initial Velocity Vo (micromoles/min)

erythromycin	no inhibitor	1 mM inhibitor	2 mM inhibitor
1	0.059	0.045	0.037
2	0.105	0.082	0.071
4	0.174	0.144	0.119
6	0.222	0.190	0.160
8	0.258	0.210	0.197
16	0.340	0.310	0.281

Display the data on a Lineweaver-Burk plot in order to extractthe Km and Vmax values. You can
generate the plot by hand on the graph paper on the last page oruse a program, such as Excel, to plot the data. Submit the plot yougenerate with your test answers.

b) What are the KM and Vmax values for each of the samples? Showyour calculations and explain how you obtain the answer for the “noinhibitor” sample.

c) What type of inhibitor is C23? Explain your answer.

d) Calculate the turnover number and the specificity constantfor the enzyme sample that lacks the inhibitor C23.