Each step in the process below has a 70.0% yield. CH4+4Cl2-->CCl4+4HCl CCl4+2HF-->CCl2F2+2HCl The CCl4 formed in the first...

90.2K

Verified Solution

Question

Chemistry

Each step in the process below has a 70.0% yield.

CH4+4Cl2-->CCl4+4HCl

CCl4+2HF-->CCl2F2+2HCl

The CCl4 formed in the first step is used as a reactant in thesecond step. If 7.00 mol of CH4 reacts, what is the total amount ofHCl produced? Assume that Cl2 and HF are present in excess.

Answer & Explanation Solved by verified expert
4.2 Ratings (870 Votes)
The CCl4 formed in the first step is used as a reactant in the second step If 700 mol of CH4 reacts what is the total amount of HCl produced Assume that Cl2 and HF are present in excess If 7 mole CH4 reacts in the first stage you will get 07 x 4 x 7    See Answer
Get Answers to Unlimited Questions

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Membership Benefits:
  • Unlimited Question Access with detailed Answers
  • Zin AI - 3 Million Words
  • 10 Dall-E 3 Images
  • 20 Plot Generations
  • Conversation with Dialogue Memory
  • No Ads, Ever!
  • Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!
Become a Member

Other questions asked by students