Each step in the process below has a 70.0% yield.
CH4+4Cl2-->CCl4+4HCl
CCl4+2HF-->CCl2F2+2HCl
The CCl4 formed in the first...
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Chemistry
Each step in the process below has a 70.0% yield.
CH4+4Cl2-->CCl4+4HCl
CCl4+2HF-->CCl2F2+2HCl
The CCl4 formed in the first step is used as a reactant in thesecond step. If 7.00 mol of CH4 reacts, what is the total amount ofHCl produced? Assume that Cl2 and HF are present in excess.
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The CCl4 formed in the first step is used as a reactant in the second step If 700 mol of CH4 reacts what is the total amount of HCl produced Assume that Cl2 and HF are present in excess If 7 mole CH4 reacts in the first stage you will get 07 x 4 x 7
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