During the standardization of NaOH, the mass of pure potassium biphthalate is 0.3001 g. The volume...

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During the standardization of NaOH, the mass of pure potassiumbiphthalate is 0.3001 g. The volume of NaOH used is 13.54 mL. Whatis the molarity of the NaOH solution in M to 3 decimal places?Molecular weight NaOH: 39.997 Molecular weight potassiumbiphthalate: 204.263 g/mol

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4.3 Ratings (614 Votes)

    KHC8H4O4 (aq) + NaOH(aq) -------------> NaKC8H4O4 + H2O

1 mole                     1mole

no of moles of KHP   = W/G.M.Wt

                                 = 0.3001/204.263   = 0.00147 moles

1 mole of KHP react with 1 mole of NaOH

0.00147 moles of KHP react with 0.00147 moles of NaOH

no of moles of NaOH   = molarity * volume in L

                0.00147        = molarity * 0.01354

           molarity           = 0.00147/0.01354    = 0.109M

molarity of NaOH = 0.109M


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