Dr. Stambaugh hypothesizes that a novel anxiety drug will affectmemory. To examine this, the drug is administered to a randomsample of 23 trained rats. The rats were then placed in a maze andtimed on how long it took them to complete it. The averagecompletion time was 47 seconds. Normal rats have an averagecompletion time of 44 seconds with a standard deviation of 14seconds. What can Dr. Stambaugh conclude with α = 0.01?
a) State the appropiate appropriate test statistic(na, z-test, one sample t test, independent- samples t test,related sample t test), population (normal rats, memory, trainedrats, time to complete maze, the maze), and sample (normal rats,memory, trained rats, time to complete maze, the maze).
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b) Compute the appropriate test statistic(s) tomake a decision about H0.
(Hint: Make sure to write down the null and alternative hypothesesto help solve the problem.)
critical value =Â Â ; test statistic =Â Â
Decision:Â Â ---Select--- Reject H0 Fail to reject H0
c) If appropriate, compute the CI. If notappropriate, input \"na\" for both spaces below.
[  ,  ]
d) Compute the corresponding effect size(s) andindicate magnitude(s).
If not appropriate, input and select \"na\" below.
d =  ;   ---Select--- na, trivial effect ,smalleffect ,medium effect , or large effect
r2 =  ;   ---Select--- na trivialeffect small effect medium effect large effect
Now, Make an interpretation based on theresults.
Rats on the anxiety drug were significantly slower completingthe maze.
Rats on the anxiety drug were significantly quicker completingthe maze.    T
he anxiety drug did not affect rats in completing the maze.