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DQ 11: Given that the solubility product of PbI2 is expressed as Ksp = [Pb2+][I–]2, calculate the Ksp...

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Chemistry

DQ 11: Given that the solubility product ofPbI2 is expressed as Ksp =[Pb2+][I–]2, calculate theKsp of PbI2 from the concentrationof Pb2+ found in Step 6 of the Data Analysis. (Hint:Think about the stoichiometry involved when PbI2 wasinitially formed… how much I– was left unreacted?) IsPbI2 a soluble or insoluble salt? Explain.

3mL of 0.05M KI was used and 1mL of 0.05 Pb(NO3)2 was used tomake the PbI2 solution/yellow precipitate

All work must be shown below for credit.

(2 pts) Show a properly balanced chemical equation:

Pb(NO3)2(aq)+ 2KI(aq)-->PbI2(s)+2KNO-3(aq)

(4 pts) Determine the limiting reagent:

(2 pts) Calculate the Ksp ofPbI2:

(2 pts) Is PbI2 a soluble or insoluble salt?Explain:

Answer & Explanation Solved by verified expert
3.6 Ratings (504 Votes)

moles of KI = 3 x 0.05 / 1000 = 1.5 x 10^-4

moles of Pb(NO3)2 = 1 x 0.05 / 1000 = 5.0 x 10^-5

a)

balanced chemical equation :

Pb(NO3)2 (aq)   + 2 KI (aq)    ------------->   PbI2 (s) + 2 KNO3 (aq)

b)

Pb(NO3)2 (aq)   + 2 KI (aq)    ------------->   PbI2 (s) + 2 KNO3 (aq)

    1                           2

5 x 10^-5             1.5 x 10^-4

here limting reagent is Pb(NO3)2.

because the mole ratio of Pb(NO3)2 is snall.

c)

PbI2 (s)   ----------------->   Pb2+   +   2 I-

Ksp = [Pb2+][I-]^2

       = (0.0125) (0.0375)^2

Ksp of PbI2 = 1.76 x 10^-5

d)

PbI2 is a insoluble salt.
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