A:- By applying the formula, M1V1 = M2V2 we have to solve this
problem,
Initial
values                                                     Â
Final
values
M1 = 6.00
MÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
M2 = 0.435 M
V1 =
?                                                            Â
V2 = 500 mL
V1 = ( M2 * V2 ) / M1
    = ( 0.435 * 500 ) / 6.00
V1 = 36.25 mL
By taking 36.25 mL of 6.00 M HNO3 in measuring jar and make it
diluted up to 500 mL by adding distilled water, hence we get 500 mL
of 0.435 M HNO3 solution.
