Describe how to make 500mL 0.435 M HNO3 from a 6.00M HNO3 solution. (Titration Lab)

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Chemistry

Describe how to make 500mL 0.435 M HNO3 from a 6.00M HNO3solution. (Titration Lab)

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A:- By applying the formula, M1V1 = M2V2 we have to solve this problem,

Initial valuesÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Final values

M1 = 6.00 MÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â M2 = 0.435 M

V1 = ?Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â V2 = 500 mL

V1 = ( M2 * V2 ) / M1

Â Â Â Â = ( 0.435 * 500 ) / 6.00

V1 = 36.25 mL

By taking 36.25 mL of 6.00 M HNO3 in measuring jar and make it diluted up to 500 mL by adding distilled water, hence we get 500 mL of 0.435 M HNO3 solution.

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