Consider the titration of a 28.0-mL sample of 0.180 M CH3NH2 with 0.145 M HBr. (The...

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Chemistry

Consider the titration of a 28.0-mL sample of 0.180 M CH3NH2with 0.145 M HBr. (The value of Kb for CH3NH2 is4.4×10−4.)

Determine the pH after adding 6.0 mL of acid beyond theequivalence point.

Express your answer using two decimal places.

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4.3 Ratings (565 Votes)
Beyond the equivalence point the pH is controlled by the excess amount of HBr Thus pH due to 60 mL of HBr can be calculated as follows Number of moles of H Number of moles of HBr Number of moles of H Volume L x    See Answer
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