Consider the following reactions: Zn^2+ + 4H3 <----> Zn(NH3)4^2+ beta 4 = 5.01 x 10^8 Zn^2+ +...

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Chemistry

Consider the following reactions:

Zn^2+ + 4H3 <----> Zn(NH3)4^2+ beta 4 = 5.01 x 10^8

Zn^2+ + 2e^- <-----> Zn(s) E degree = -0.762 V

Assuming there is negligible current and nearly all Zn^2+ is inthe form Zn(NH3)4^2+. what cathode potential (vs. S.H.E.) would berequired to reduce 99.99% of the Zn^2+ from a solution containing0.20 M Zn^2+ in 1.4 M ammonia? (Assume T= 298 K)

________V

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3.8 Ratings (559 Votes)
For the half cell Zn2 2e Zns Eo 0762 V Eo 00592 V2logK 00296V x logK logK 0762 V00296 V 2574 K 102574    See Answer
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