Consider the following reaction Fe3 (aq) SCN(aq)FeSCN2 (aq) Asolution...

Fe3aq SCNaq FeSCN2aq 12x103 78 x 104 0 initial 12x103x 78 x 10 ....

Consider the following reaction: Fe3+(aq)+SCNâˆ’(aq)â‡ŒFeSCN2+(aq) A solution is made containing an initial [Fe3+] of 1.2Ã—10âˆ’3 M...

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Chemistry

Consider the following reaction: Fe3+(aq)+SCNâˆ’(aq)â‡ŒFeSCN2+(aq) Asolution is made containing an initial [Fe3+] of 1.2Ã—10âˆ’3 M and aninitial [SCNâˆ’] of 7.8Ã—10âˆ’4 M . At equilibrium, [FeSCN2+]= 1.7Ã—10âˆ’4M .Calculate the value of the equilibrium constant (Kc).

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4.1 Ratings (455 Votes)

Fe3+(aq)Â Â + SCNâˆ’(aq) <--------------------> FeSCN2+(aq)

1.2x10^-3Â Â Â Â 7.8 x 10^-4Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â Â Â Â ----------------> initial

1.2x10^-3-x Â Â Â 7.8 x 10^-4 -x Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â x Â Â Â Â Â Â Â Â Â Â Â ---------------->equilibrium

but x = 1.7 x 10^-4 is given

equilibrium concentrations :

[Fe+2] = 1.2x10^-3-xÂ Â = 1.03 x 10^-3 M

[SCN-] = 7.8 x 10^-4 -x = 6.1 x 10^-4 M

[FeSCN2+]= 1.7Ã—10^âˆ’4 M

equilibrium constant (Kc)Â Â = [FeSCN2+] / [Fe+2] [SCN-]

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 1.7Ã—10^âˆ’4 / (1.03 x 10^-3 ) (6.1 x 10^-4)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 270.6

equilibrium constant (Kc)Â Â = 270.6

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