Consider the following reaction : Fe3+ (aq) + SCN- (aq) ---> Fe(SCN)2+ (aq) Starting with 4.00 mL of...

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Chemistry

Consider the following reaction :

Fe3+ (aq) + SCN- (aq) --->Fe(SCN)2+ (aq)

Starting with 4.00 mL of .200 M Fe3+ (aq) in acuvette, 0.10 mL increments of 0.00100 M SCN- (aq) willbe added. Assume that because [Fe3+ (aq)] >>[SCN- (aq)], the [Fe(SCN)2+] concentrationcan be calculated from the limiting reagent, SCN-.Calculate [Fe(SCN)2+].

Volume .00100 M KSCN mL[Fe(SCN)2+] (M)
.10
.20
.30
.40
.50
.60
.70
.80
.90
1.00

Answer & Explanation Solved by verified expert
3.9 Ratings (355 Votes)
Solution using the molarity and volume sof the each we calculate the moles of the SCN and then use them as the moles opf product because mole ratio is 1 1 then calculate the concnetration of the FeSCN2 at total volume in each part following are the calculations for each part Moles of Fe3 molarity volume in liter 0200 mol per L 0004 L 00008 mol Moles of SCN part 1 0001 mol per L 00001 L 1107 So moles of FeSCN2 produced 1107 mol Molarity    See Answer
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