Consider the following reaction 2 A B P A table of initialrates wi...

Let the rate is r kA x B y A 0 B 0 r 02 01 1210 5 i 04 01 2410 5 ii 0 ....

Consider the following reaction. 2 A + B âˆ’â†’ P A table of initial rates with...

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Consider the following reaction. 2 A + B âˆ’â†’ P A table of initialrates with initial concentrations of A and B is given below. [A]o(M) [B]o (M) rate M s 0.2 0.1 1.2 Ã— 10âˆ’5 0.4 0.1 2.4 Ã— 10âˆ’5 0.4 0.29.2 Ã— 10âˆ’5 0.1 0.1 6.0 Ã— 10âˆ’6 What is the rate expression? (a) r =k[A] [B]2 (b) r = k[A] [B] (c) r = k[A]2 [B] (d) r = k[A]2 [B]2

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3.8 Ratings (486 Votes)

Let the rate is, r = k[A]^x [B]^y

[A]⁰Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â [B]⁰Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â r

0.2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.1Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 1.2*10^{-5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â} (i)

0.4Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.1Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 2.4*10^{-5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â} (ii)

0.4Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 9.2*10^-5Â Â Â Â Â Â Â Â Â Â Â Â Â Â (iii)

0.1Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.1Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 6.0*10^{-6Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â} (iv)

from, (i)

r =1.2*10^-5= k[A]^x [B]^y = k[0.2]^x [0.1]^y........1

from, (ii)

r =2.4*10^-5= k[A]^x [B]^y = k[0.4]^x [0.1]^y............2

deviding 2 by 1 we get,

2^x = 2

so, x = 1

from, (iii)

r =9.2*10^-5= k[A]^x [B]^y = k[0.4]^x [0.2]^y............3

deviding 3 by 2 we get,

2^y = 3.8 = 4 (almost)

so, y = 2

the rate is, r= k[A]^x [B]^y = k[A] [B]²

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Consider the following reaction. 2 A + B âˆ’â†’ P A table of initial rates with...

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