Consider the following code:
void swap(int arr[], int i, int j) {
       int temp = arr[i];
       arr[i] = arr[j];
       arr[j] = temp;
}
void function(int arr[], int length)
{
       for (int i = 0;i              swap(arr,i, (length / 2 + i) % length);
}
If the input to the function was int arr[] = { 6, 1, 8, 2, 5, 4, 3, 7 }; function(arr,8);What values would be stored in the array after calling the function?What is the output of the following code?  (as alwaysindicate \"error\" if there is any kind of runtime or compile-timeerror or \"infinite\" if there is an infinite loop)
void swap(int &a, int &b)
{
       int t = a;
       a = b;
       b = t;
}
void function(int arr[], int arr2[], int length)
{
       for (int i = 0;i       {
              swap(arr[i],arr[(i + arr2[i]) % length]);
       }
}
int main()
{
       int arr1[] = { 5, 2,3, 7, 1, 6, 8, 4 };
       int arr2[] = { 1, 4,-2, -1, 2, 7, 2, 1 };
       function(arr1, arr2,8);
       for (int a : arr1)
              cout<< a << \" \";
}
