Consider the evaporation of methanol at 25.0 ?C :
CH3OH(l)?CH3OH(g) .
Why methanol spontaneously evaporates in open air at 25.0 ?C :Methanol evaporates at room temperature because there is anequilibrium between the liquid and the gas phases. The vaporpressure is moderate (143 mmHg at 25.0 degrees centigrade), so amoderate amount of methanol can remain in the gas phase, which isconsistent with the free energy values.
A.) Find ?G? at 25.0 ?C .
B.) Find ?G at 25.0 ?C under the following nonstandardconditions:
(i)PCH3OH= 158.0mmHg
C). Find ?G at 25.0 ?C under the following nonstandardconditions:
(ii) PCH3OH= 110.0mmHg
D.) Find ?G at 25.0 ?C under the following nonstandardconditions:
(iii) PCH3OH= 11.0mmHg
